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The School Thread
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| Ian Butler |
Posted on 28-09-2012 06:58
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Sounds like an interesting job! Hope you have a better time at that school, though  |
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| Ad Bot |
Posted on 21-11-2024 17:41
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| Mresuperstar |
Posted on 02-10-2012 23:00
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Agh first two exams of the year... C's. I need to keep a 3.15 GPA to keep my scholarship. Not good, but that's what I get for cramming all my basics class into my first year. 
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| Levi4life |
Posted on 02-10-2012 23:20
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This is our first week of instruction.  midterms are in a month and finals are a early December. I've heard people complain that the quarter system is too hectic but I think I'm going to like it. We start later and end earlier than my friends at the junior college I went too.
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| maxime86 |
Posted on 04-10-2012 00:29
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acac wrote:
jsh312mufc wrote:
acac wrote:
maxime86 wrote:
anyone else in middle school?
you are in middle school?then RIP.
in the middle school i went to 3 teachers went to jail in just 6 months(1 used drugs during teaching, one pushed a student from the stairs and on sexualy harrested a student). at least now when i say that my teacher acts odd, people belive me.
usa sounds fun. middle school is what age for people who dont know?
well, here its 7th to 9th grade.
dont know about USA though.
13 usually in eighth grade which I am in |
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| SweatyViking |
Posted on 12-10-2012 21:41
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I need help with a math problem... Can someone explain how to solve it?
3x(x – 2)(x – 1) – 2x(2x – 3)2 (the 2 at the end is an exponent)
Edited by SweatyViking on 12-10-2012 21:41
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| Ian Butler |
Posted on 12-10-2012 21:43
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You have no "="? Or what do we have to do with it? |
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| Aquarius |
Posted on 12-10-2012 21:57
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Is the first x a multiplication sign or an actual x ? |
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| Pellizotti2 |
Posted on 12-10-2012 22:03
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Aquarius wrote:
Is the first x a multiplication sign or an actual x ?
I think it's an x. I've been working with similar things lately.
What are you supposed to do with the problem? Shorten it?
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| sammyt93 |
Posted on 12-10-2012 23:04
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SweatyViking wrote:
I need help with a math problem... Can someone explain how to solve it?
3x(x – 2)(x – 1) – 2x(2x – 3)2 (the 2 at the end is an exponent)
you need to simplfy it first which, assuming by exponent you mean the bit in the last lot of brackets is to the power of 2 or squared you can do as follows:
the first thing you need to do is to times together the double brackets to get them in one bracket.
e.g.
(x - 2)(x - 1) so that it would become (x^2 -2x -x +3)
which when you collect the like terms becomes (x^2-3x+3)
then you need to times that through by the 3x infront of the bracket.
so that would be (3x^3 -9x^2 +9x)
it would now look like this: (3x^3-9x^2+9x) -2x(2x-3)^2
then you would need to work on the second half which would mean squaring what's in the brackets as follows:
(2x-3)(2x-3) this would become (4x^2-6x-6x+9)
then you collect together the like terms to get (4x^2-12x+9)
again you would need to times that through by what's infront of the brackets, in this case the 2x.
so that would become: (8x^3-24x^2+18x)
then when you put it back in the equation you would get:
(3x^3 -9x^2 +9x) - (8x^3-24x^2+18x)
then you again collect the like terms, not forgetting that the second set of barckets is taken away from the first set, this basically mean you would be switching all the positive and negative signs over in the second set of brackets when you collect the terms together.
that would leave you with:
-5x^3+15x^2-9x
normally you need to make it look better by the writing it as 15x^2 -5x^3-9x.
i'm not 100% sure on the next bit but i'm fairly sure you would need to make it equal to 0, find the 3 factors and then solve each of them. problem is I can't remember that bit but hopefully this will at least help up to that point and help either you or someone else finish off how to do it. |
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| felix_29 |
Posted on 12-10-2012 23:04
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I think you made a mistake from the first to the second line. As far as i know, you first have to calculate (2x-3)² and then multiply it with 2x. And -2*-1 makes +2. So my solution is:
3x(x²-x-2x+2) - 2x(4x²-12x+9)
3x³ - 3x² - 6x² + 6x - 8x³ + 24x² - 18x
(...)
-5x³ + 15x² -12x
Didn´t double check my answer, so most likely i made some oversights, too.
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| ggDonovan |
Posted on 12-10-2012 23:07
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Check this out:
https://www.wolfra...
*Note: Be careful, you won't have Wolfram in your exams.
This is like... At your save at home you can win the TDF having modified all the stats of your riders to have 85 in all the stats and nobody will now it. But this is not possible in ManGame
Edited by ggDonovan on 12-10-2012 23:09
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| johnnyjur |
Posted on 12-10-2012 23:15
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sammyt93 wrote:
SweatyViking wrote:
I need help with a math problem... Can someone explain how to solve it?
3x(x – 2)(x – 1) – 2x(2x – 3)2 (the 2 at the end is an exponent)
you need to simplfy it first which, assuming by exponent you mean the bit in the last lot of brackets is to the power of 2 or squared you can do as follows:
the first thing you need to do is to times together the double brackets to get them in one bracket.
e.g.
(x - 2)(x - 1) so that it would become (x^2 -2x -x +3)
which when you collect the like terms becomes (x^2-3x+3)
then you need to times that through by the 3x infront of the bracket.
so that would be (3x^3 -9x^2 +9x)
it would now look like this: (3x^3-9x^2+9x) -2x(2x-3)^2
then you would need to work on the second half which would mean squaring what's in the brackets as follows:
(2x-3)(2x-3) this would become (4x^2-6x-6x+9)
then you collect together the like terms to get (4x^2-12x+9)
again you would need to times that through by what's infront of the brackets, in this case the 2x.
so that would become: (8x^3-24x^2+18x)
then when you put it back in the equation you would get:
(3x^3 -9x^2 +9x) - (8x^3-24x^2+18x)
then you again collect the like terms, not forgetting that the second set of barckets is taken away from the first set, this basically mean you would be switching all the positive and negative signs over in the second set of brackets when you collect the terms together.
that would leave you with:
-5x^3+15x^2-9x
normally you need to make it look better by the writing it as 15x^2 -5x^3-9x.
i'm not 100% sure on the next bit but i'm fairly sure you would need to make it equal to 0, find the 3 factors and then solve each of them. problem is I can't remember that bit but hopefully this will at least help up to that point and help either you or someone else finish off how to do it.
Looks fairly correct, BUT (-2 X -1) = 2, not 3
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| sammyt93 |
Posted on 12-10-2012 23:21
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Classics Specialist
Posts: 3634
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johnnyjur wrote:
sammyt93 wrote:
SweatyViking wrote:
Spoiler I need help with a math problem... Can someone explain how to solve it?
3x(x – 2)(x – 1) – 2x(2x – 3)2 (the 2 at the end is an exponent)
you need to simplfy it first which, assuming by exponent you mean the bit in the last lot of brackets is to the power of 2 or squared you can do as follows:
the first thing you need to do is to times together the double brackets to get them in one bracket.
e.g.
(x - 2)(x - 1) so that it would become (x^2 -2x -x +3)
which when you collect the like terms becomes (x^2-3x+3)
then you need to times that through by the 3x infront of the bracket.
so that would be (3x^3 -9x^2 +9x)
it would now look like this: (3x^3-9x^2+9x) -2x(2x-3)^2
then you would need to work on the second half which would mean squaring what's in the brackets as follows:
(2x-3)(2x-3) this would become (4x^2-6x-6x+9)
then you collect together the like terms to get (4x^2-12x+9)
again you would need to times that through by what's infront of the brackets, in this case the 2x.
so that would become: (8x^3-24x^2+18x)
then when you put it back in the equation you would get:
(3x^3 -9x^2 +9x) - (8x^3-24x^2+18x)
then you again collect the like terms, not forgetting that the second set of barckets is taken away from the first set, this basically mean you would be switching all the positive and negative signs over in the second set of brackets when you collect the terms together.
that would leave you with:
-5x^3+15x^2-9x
normally you need to make it look better by the writing it as 15x^2 -5x^3-9x.
i'm not 100% sure on the next bit but i'm fairly sure you would need to make it equal to 0, find the 3 factors and then solve each of them. problem is I can't remember that bit but hopefully this will at least help up to that point and help either you or someone else finish off how to do it.
Looks fairly correct, BUT (-2 X -1) = 2, not 3
i was always making stupid mistakes like that when i took my GCSE's but managed to get rid of them for the exams. |
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| Ian Butler |
Posted on 13-10-2012 07:48
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Tour de France Champion
Posts: 21854
Joined: 01-05-2012
PCM$: 400.00
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I always made concentration mistakes like suddenly dropping a exponent, or writing so ugly that a 2 became a +  |
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| Zoom123 |
Posted on 13-10-2012 09:01
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Oh boy, got exams in a few weeks. Need to find the willpower to study. But after this next term I'm on summer holidays woot woot
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| CrueTrue |
Posted on 13-10-2012 19:38
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Summer seems so far away right now. 5 months of extreme cold waiting ahead |
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| FroomeDog99 |
Posted on 13-10-2012 19:38
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CrueTrue wrote:
Summer seems so far away right now. 5 months of extreme cold waiting ahead
Tell me about it  |
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| Levi4life |
Posted on 13-10-2012 20:14
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You could always move to Southern California. There is room in my apartment. The high of the last 2 days was about 70 Fahrenheit, with a few millimeters of rain. The weekend and rest of the week is supposed to be mid to high 80's.
Frankly I would rather live in Denmark
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| FreitasPCM |
Posted on 13-10-2012 22:02
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1 month down, 8 to go.  |
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| Ian Butler |
Posted on 14-10-2012 08:03
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Tour de France Champion
Posts: 21854
Joined: 01-05-2012
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CrueTrue wrote:
Summer seems so far away right now. 5 months of extreme cold waiting ahead
I guess in Denmark it must be pretty depressing when it's winter. You probably don't get many sunlight then.
But on the bright side: there's more suicide in Belgium than in Denmark, so you probably won't kill yourself over it |
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